49b^2-64=0

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Solution for 49b^2-64=0 equation:



49b^2-64=0
a = 49; b = 0; c = -64;
Δ = b2-4ac
Δ = 02-4·49·(-64)
Δ = 12544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12544}=112$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-112}{2*49}=\frac{-112}{98} =-1+1/7 $
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+112}{2*49}=\frac{112}{98} =1+1/7 $

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